4.9x^2+2.4x-1.6=0

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Solution for 4.9x^2+2.4x-1.6=0 equation:



4.9x^2+2.4x-1.6=0
a = 4.9; b = 2.4; c = -1.6;
Δ = b2-4ac
Δ = 2.42-4·4.9·(-1.6)
Δ = 37.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{37.12}}{2*4.9}=\frac{-2.4-\sqrt{37.12}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{37.12}}{2*4.9}=\frac{-2.4+\sqrt{37.12}}{9.8} $

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